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98=2x^2
We move all terms to the left:
98-(2x^2)=0
a = -2; b = 0; c = +98;
Δ = b2-4ac
Δ = 02-4·(-2)·98
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28}{2*-2}=\frac{-28}{-4} =+7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28}{2*-2}=\frac{28}{-4} =-7 $
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